from itertools import accumulate as ac;r=lambda:map(int,input().split());t,=r();f=lambda i:p[i]-k*i+sum(a[i+j]>>(j+1)for j in range(min(n-i,30)))
while t:t-=1;n,k=r();a=[*r()];p=[0]+list(ac(a));print(max(f(i)for i in range(n+1)))
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
void solve() {
int n, k;
cin >> n >> k;
vector<ll> a(n);
for (auto &x: a) cin >> x;
vector<vector<ll>> dp(n + 1, vector<ll>(31, -1e18));
dp[0][0] = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j <= min(i + 1, 30); j++) {
dp[i + 1][j] = max(dp[i + 1][j], dp[i][j] - k + (a[i] / (1 << j)));
int nxt = min(30, j + 1);
dp[i + 1][nxt] = max(dp[i + 1][nxt], dp[i][j] + (a[i] / (1 << nxt)));
}
}
cout << *max_element(dp[n].begin(), dp[n].end());
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while (t--) {
solve();
cout << '\n';
}
}
One String No Trouble | Help Jarvis! |
Lift queries | Goki and his breakup |
Ali and Helping innocent people | Book of Potion making |
Duration | Birthday Party |
e-maze-in | Bricks Game |
Char Sum | Two Strings |
Anagrams | Prime Number |
Lexical Sorting Reloaded | 1514A - Perfectly Imperfect Array |
580A- Kefa and First Steps | 1472B- Fair Division |
996A - Hit the Lottery | MSNSADM1 Football |
MATCHES Playing with Matches | HRDSEQ Hard Sequence |
DRCHEF Doctor Chef | 559. Maximum Depth of N-ary Tree |
821. Shortest Distance to a Character | 1441. Build an Array With Stack Operations |
1356. Sort Integers by The Number of 1 Bits | 922. Sort Array By Parity II |
344. Reverse String | 1047. Remove All Adjacent Duplicates In String |